Question:
How much should the pressure be increased in order to reduce the volume of a given mass of gas by \(5 \%\) at the constant temperature?
How much should the pressure be increased in order to reduce the volume of a given mass of gas by \(5 \%\) at the constant temperature?
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At constant temperature use Boyle's law, P1 V1 = P2 V2.
Updated On: Nov 13, 2026
- \(5\%\)
- \(10\%\)
- \(5.26\%\)
- \(4\%\)
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept
At constant temperature Boyle's law holds: \(PV=\text{constant}\).
Step 2: New volume
The volume reduces by 5 percent, so \(V_2=0.95V\).
Step 3: New pressure
\(P_2=\dfrac{PV}{0.95V}=1.0526P\).
Step 4: Percentage increase
\(\dfrac{P_2-P}{P}\times100=5.26\%\)
Final Answer:
The pressure must be increased by about 5.26 percent. \[ \boxed{\text{(C) }5.26\%} \]
At constant temperature Boyle's law holds: \(PV=\text{constant}\).
Step 2: New volume
The volume reduces by 5 percent, so \(V_2=0.95V\).
Step 3: New pressure
\(P_2=\dfrac{PV}{0.95V}=1.0526P\).
Step 4: Percentage increase
\(\dfrac{P_2-P}{P}\times100=5.26\%\)
Final Answer:
The pressure must be increased by about 5.26 percent. \[ \boxed{\text{(C) }5.26\%} \]
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