Step 1: Writing the structure.
2-iodo-3,3-dimethylpentane has a pentane backbone with two methyl groups at C-3 and iodine at C-2.
Step 2: Identifying tertiary carbons.
No carbon atom is attached to three other carbon atoms, so tertiary carbon atoms = 0.
Step 3: Identifying primary carbons.
The terminal carbons and methyl substituents contribute four primary carbon atoms.
Step 4: Conclusion.
Hence, the correct answer is 0 tertiary and 4 primary carbon atoms.