Question:
How many moles of \(\mathrm{Al}_2(\mathrm{SO}_4)_3\) would be in \(50\mathrm{g}\) of the substance?
How many moles of \(\mathrm{Al}_2(\mathrm{SO}_4)_3\) would be in \(50\mathrm{g}\) of the substance?
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Always double-check the atomic masses: Al = 27, S = 32, O = 16.
Updated On: Apr 20, 2026
- 0.0843 mol
- 0.952 mol
- 0.481 mol
- 0.140 mol
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The Correct Option is D
Solution and Explanation
Step 1: Understanding the Concept:
Number of moles = Mass / Molar mass.
Step 2: Detailed Explanation:
Molar mass of \(\mathrm{Al}_2(\mathrm{SO}_4)_3 = 2 \times 27 + 3 \times (32 + 4 \times 16) = 54 + 3 \times 96 = 54 + 288 = 342 \mathrm{g/mol}\).
Moles = \(\frac{50}{342} = 0.146 \mathrm{mol} \approx 0.140 \mathrm{mol}\).
Step 3: Final Answer:
0.140 mol
Number of moles = Mass / Molar mass.
Step 2: Detailed Explanation:
Molar mass of \(\mathrm{Al}_2(\mathrm{SO}_4)_3 = 2 \times 27 + 3 \times (32 + 4 \times 16) = 54 + 3 \times 96 = 54 + 288 = 342 \mathrm{g/mol}\).
Moles = \(\frac{50}{342} = 0.146 \mathrm{mol} \approx 0.140 \mathrm{mol}\).
Step 3: Final Answer:
0.140 mol
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