Question:
How many moles of iodomethane are consumed in the following conversion?
$\text{CH}_3\text{NH}_2 \xrightarrow[\Delta]{\text{CH}_3\text{I}} (\text{CH}_3)_4\text{N}^+ \text{I}^-$}
How many moles of iodomethane are consumed in the following conversion?
$\text{CH}_3\text{NH}_2 \xrightarrow[\Delta]{\text{CH}_3\text{I}} (\text{CH}_3)_4\text{N}^+ \text{I}^-$}
$\text{CH}_3\text{NH}_2 \xrightarrow[\Delta]{\text{CH}_3\text{I}} (\text{CH}_3)_4\text{N}^+ \text{I}^-$}
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Rule:
Primary amine $\rightarrow$ quaternary ammonium needs 3 alkylations
Updated On: May 8, 2026
- Four
- Three
- Two
- One
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Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Concept: Alkylation of amines proceeds stepwise.
Step 1: Track methylation.
• $\text{CH}_3\text{NH}_2 \rightarrow (\text{CH}_3)_2\text{NH}$ (1 mole CH$_3$I)
• $\rightarrow (\text{CH}_3)_3\text{N}$ (2 moles CH$_3$I total)
• $\rightarrow (\text{CH}_3)_4\text{N}^+$ (3 moles CH$_3$I total)
Step 2: Conclusion.
Total iodomethane required = 3 moles. Final Answer: Option (B)
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