Question:
How many moles of hydrogen are liberated when \(6\) moles of ethyl alcohol reacts with sodium metal?
How many moles of hydrogen are liberated when \(6\) moles of ethyl alcohol reacts with sodium metal?
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Two moles of ethanol give one mole of hydrogen with sodium.
Updated On: Oct 1, 2026
- \(2\)
- \(3\)
- \(4\)
- \(6\)
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept:
Alcohols react with sodium metal to give sodium alkoxide and hydrogen gas. The balanced equation tells the mole ratio.
Step 2: Balanced equation:
\[ 2\text{C}_2\text{H}_5\text{OH} + 2\text{Na} \to 2\text{C}_2\text{H}_5\text{ONa} + \text{H}_2 \]
Step 3: Calculate:
\(2\) mol of ethanol give \(1\) mol of \(\text{H}_2\). So \(6\) mol of ethanol give \(\frac{6}{2} = 3\) mol of \(\text{H}_2\).
Step 4: Other options:
\(6\) mol would be the answer if each ethanol released one \(\text{H}_2\). Each molecule only has one acidic hydrogen (the O-H), and two such hydrogens are needed per \(\text{H}_2\).
Final Answer:
Three moles of hydrogen are liberated, option (B). \[ \boxed{3\ \text{mol}} \]
Alcohols react with sodium metal to give sodium alkoxide and hydrogen gas. The balanced equation tells the mole ratio.
Step 2: Balanced equation:
\[ 2\text{C}_2\text{H}_5\text{OH} + 2\text{Na} \to 2\text{C}_2\text{H}_5\text{ONa} + \text{H}_2 \]
Step 3: Calculate:
\(2\) mol of ethanol give \(1\) mol of \(\text{H}_2\). So \(6\) mol of ethanol give \(\frac{6}{2} = 3\) mol of \(\text{H}_2\).
Step 4: Other options:
\(6\) mol would be the answer if each ethanol released one \(\text{H}_2\). Each molecule only has one acidic hydrogen (the O-H), and two such hydrogens are needed per \(\text{H}_2\).
Final Answer:
Three moles of hydrogen are liberated, option (B). \[ \boxed{3\ \text{mol}} \]
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