Question:
How many grams of $ \text{CO}_2 $ are produced when 10 g of $ \text{C}_2\text{H}_6 $ (ethane) is completely combusted?
Reaction: $ 2\text{C}_2\text{H}_6 + 7\text{O}_2 \rightarrow 4\text{CO}_2 + 6\text{H}_2\text{O} $
How many grams of $ \text{CO}_2 $ are produced when 10 g of $ \text{C}_2\text{H}_6 $ (ethane) is completely combusted?
Reaction: $ 2\text{C}_2\text{H}_6 + 7\text{O}_2 \rightarrow 4\text{CO}_2 + 6\text{H}_2\text{O} $
Show Hint
To solve stoichiometry problems involving mass-to-mass conversions:
\begin{enumerate}
\item \textbf{Balance the Chemical Equation:} Ensure the reaction is correctly balanced to determine the correct mole ratios between reactants and products.
\item \textbf{Calculate Molar Masses:} Determine the molar mass of the given substance and the substance you need to find.
\item \textbf{Convert Given Mass to Moles:} Use the molar mass to convert the given mass of the substance into moles.
\item \textbf{Use Mole Ratio (Stoichiometry):} From the balanced equation, use the stoichiometric coefficients to find the mole ratio between the given substance and the desired substance. Use this ratio to convert moles of the given substance to moles of the desired substance.
\item \textbf{Convert Moles to Desired Mass:} Use the molar mass of the desired substance to convert its moles back into grams.
\end{enumerate}
Updated On: Jan 13, 2026
- 29.3 g
- 44.0 g
- 58.6 g
- 88.0 g
Show Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
To determine how many grams of $ \text{CO}_2 $ are produced from the complete combustion of 10 g of $ \text{C}_2\text{H}_6 $ (ethane), we follow these steps:
Step 1: Determine the molar mass of $ \text{C}_2\text{H}_6 $ and $ \text{CO}_2 $.
- Molar mass of $ \text{C}_2\text{H}_6 $: (2 x 12.01 g/mol for C) + (6 x 1.008 g/mol for H) = 30.07 g/mol
- Molar mass of $ \text{CO}_2 $: (1 x 12.01 g/mol for C) + (2 x 16.00 g/mol for O) = 44.01 g/mol
Step 2: Calculate the moles of $ \text{C}_2\text{H}_6 $ in 10 g.
Moles of $ \text{C}_2\text{H}_6 $ = $\frac{10 \text{ g}}{30.07 \text{ g/mol}}$ ≈ 0.332 mol
Step 3: Use the stoichiometry of the reaction to find moles of $ \text{CO}_2 $ produced.
The balanced reaction is: $2\text{C}_2\text{H}_6 + 7\text{O}_2 \rightarrow 4\text{CO}_2 + 6\text{H}_2\text{O}$
The molar ratio of $ \text{C}_2\text{H}_6 $ to $ \text{CO}_2 $ is 2:4 or 1:2. Therefore, 0.332 mol of $ \text{C}_2\text{H}_6 $ will produce 0.664 mol of $ \text{CO}_2 $.
Step 4: Calculate the grams of $ \text{CO}_2 $ produced.
Mass of $ \text{CO}_2 $ = 0.664 mol x 44.01 g/mol = 29.23 g
Therefore, the mass of $ \text{CO}_2 $ produced is approximately '29.3 g'.
Was this answer helpful?
0
0
Top BITSAT Chemistry Questions
- Which of the following silver salts is insoluble in water ?
- Which of the following is deliquescent ?
- Among the following sets of quantum numbers. Which one is incorrect for $4d$ electron ?
- In the purification of impure nickel by Mond's process, metal is purified by:
- When $25\, g$ of a non-volatile solute is dissolved in $100\,g$ of water, the vapour pressure is lowered by $2.25 \times 10^{-1}\, mm$. If the vapour pressure of water at $20^{\circ} C$ is $17.5\, mm$, what is the molecular weight of the solute?
View More Questions
Top BITSAT Stoichiometry and Stoichiometric Calculations Questions
- $0.45 \,g$ of acid molecular weight $90$ is neutralised by $20\, ml$ of $0.5\,N$ caustic potash. The basicity of acid is
- $3.92\,g$ of ferrous ammonium sulphate react completely with $50\, ml \frac{N}{10} KMnO_{4}$ solution. The percentage purity of the sample is
- Match the following:The correct match is
List-I List-n (At STP) (A) $10 \, g \, CaCO_3 \xrightarrow [\text{decomposition}]{\Delta}$ (i) $0.224 \, L \, CO_2$ (B) $1.06 \, g \, Na_2 CO_3 \xrightarrow{\text{Excess HCl}}$ (ii) $4.48 \, L \, CO_2$ (C) $2.4 \, g \, C \xrightarrow [\text{combustion}]{Excess \, O_2}$ (iii) $0.448 \, L \, CO_2$ (D) $0.56 \, g \, CO \xrightarrow [\text{combustion}]{\text{Excess} O_2}$ (iv) $2.24 \, L \, CO_2$ (v) $22.4 \, L \, CO_2$ - Formation of polyethylene from calcium carbide takes place as follows $ CaC _{2}+2 H _{2} O \longrightarrow Ca ( OH )_{2}+ C _{2} H _{2}$ $C _{2} H _{2}+ H _{2} \longrightarrow C _{2} H _{4} $ $ nC _{2} H _{4} \longrightarrow\left(- CH _{2}- CH _{2}-\right) n$ The amount of polyethylene obtained from $64.1\, kg$ of $CaC _{2}$ is
- $1.5 \,g$ of $CdCl_2$ was found to contain $0.9 \,g$ of $Cd$. Calculate the atomic weight of $Cd$.
View More Questions
Top BITSAT Questions
- Two point charges $-q$ and $+ q$ are located at point's $(0, 0, - a)$ and, $(0, 0, a)$ respectively. The electric potential at a point $(0, 9, z)$, where $z > a$ is
- Which of the following must be known in order to determine the power output of an automobile?
- A large drop of oil (density $0.8 \,g / cm ^{3}$ and viscosity $\eta_{0}$ ) floats up through a column of another liquid (density $1.2\, g / cm ^{3}$ and viscosity $\eta_{L}$ ). Assuming that the two liquids do not mix, the velocity with which the oil drop rises will depend on :
- A body is projected vertically upwards at time $ t = 0$ and it is seen at a height $H$ at time $t_1$ and $t_2$ second during its flight. The maximum height attained is ($g$ is acceleration due to gravity)
- At what point of a projectile motion, acceleration and velocity are perpendicular to each other ?
View More Questions