Question

How many different eight digit numbers can be formed from the number 22335588 by rearranging its digits if odd digits occupy even positions?

• A. 16
• B. 36
• C. 60
• D. 180

Hint:

When positions are fixed (odd/even), count arrangements separately and then multiply.

Answer 1

The Correct Option is B

Step 1: Digits of the number: 2,2,3,3,5,5,8,8 Even digits: 2,2,8,8 Odd digits: 3,3,5,5 Step 2: Even positions are 2,4,6,8 (4 positions). Arrange even digits: (4!)/(2!2!)=6 Step 3: Odd positions are 1,3,5,7 (4 positions). Arrange odd digits: (4!)/(2!2!)=6 Step 4: Total numbers: 6 × 6 = 36