Question:

How many ATP molecules are required to produce two $NH_{3}$ molecules during nitrogen fixation?

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Standard formula: 1 $N_2$ $\rightarrow$ 2 $NH_3$ costs 16 ATP. It takes 8 ATP to make just one ammonia molecule.
Updated On: May 20, 2026
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The Correct Option is B

Solution and Explanation

Concept: Nitrogen fixation is one of the most energetically expensive biological processes in nature because of the extreme stability of the $N_2$ triple bond.

Step 1:
Energetic Requirements of Nitrogenase.
The reduction of one molecule of $N_2$ requires 8 electrons and 8 protons. To drive the transfer of each electron from the Fe-protein to the MoFe-protein of the nitrogenase complex, 2 ATP molecules are hydrolyzed.

Step 2:
The Calculation.
Since 8 electrons are required to reduce one $N_2$ into two molecules of $NH_3$ (and one $H_2$ molecule as an obligatory byproduct), the total ATP cost is: \[ 8 \text{ electrons} \times 2 \text{ ATP/electron} = 16 \text{ ATP} \]

Step 3:
Conclusion.
Therefore, 16 ATP molecules are required to produce two molecules of ammonia.
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