Question

How is the rate of second order reaction affected when the concentration of the reactant is increased by \(2\) times its initial value ?

• A. Remains the same.
• B. It quadruples
• C. It triples
• D. It doubles

Hint:

For a second order reaction the rate is proportional to the square of the concentration.

Answer 1

The Correct Option is B

Step 1: Understanding the Concept
For a second order reaction, rate \(=k[A]^2\).

Step 2: Double the concentration
The new rate \(=k(2[A])^2=4k[A]^2\).

Step 3: Compare
The rate becomes four times the original, so it quadruples, option (B).

Final Answer:
The rate becomes four times the initial rate. \[ \boxed{\text{(B) }\text{It quadruples}} \]