Question:
Given the system of straight lines
a(2x+y-3)+b(3x+2y-5)=0,
the line of the system situated farthest from the point (4,-3) has the equation
Given the system of straight lines
a(2x+y-3)+b(3x+2y-5)=0,
the line of the system situated farthest from the point (4,-3) has the equation
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For a system of lines, extreme distances occur at boundary members of the family.
Updated On: Mar 20, 2026
- \(4x+11y-15=0\)
- \(7x+y-8=0\)
- \(4x+3y-7=0\)
- 3x-4y+1=0
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The Correct Option is B
Solution and Explanation
Step 1: A line of the system is (2x+y-3)+λ(3x+2y-5)=0.
Step 2: Distance from point (4,-3) is maximized when numerator is maximum.
Step 3: This occurs for the line 7x+y-8=0.
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