Question:

Given the system of straight lines a(2x+y-3)+b(3x+2y-5)=0, the line of the system situated farthest from the point (4,-3) has the equation

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The farthest line from a point has the maximum perpendicular distance from that point.
Updated On: Mar 19, 2026
  • 4x+y-15=0
  • 7x+y-8=0
  • 4x+3y-7=0
  • 3x-4y+1=0
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The Correct Option is D

Solution and Explanation

Step 1: A general line of the system is (2a+3b)x+(a+2b)y-(3a+5b)=0 Step 2: Distance of a line Ax+By+C=0 from point (x₀,y₀) is: D=frac|Ax₀+By₀+C|√(A²+B²) Step 3: Evaluating distances of given options from (4,-3), the maximum distance is obtained for: 3x-4y+1=0 Hence, option (D) is correct.
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