Question:
Given below is a frequency distribution with median 46. In this distribution, some of the frequencies are missing. Determine the missing frequencies.
Marks: 10–20, 20–30, 30–40, 40–50, 50–60, 60–70, 70–80
No. of students: 12, 30, x, 65, y, 25, 18
Total number of students = 229
Given below is a frequency distribution with median 46. In this distribution, some of the frequencies are missing. Determine the missing frequencies.
Marks: 10–20, 20–30, 30–40, 40–50, 50–60, 60–70, 70–80
No. of students: 12, 30, x, 65, y, 25, 18
Total number of students = 229
Marks: 10–20, 20–30, 30–40, 40–50, 50–60, 60–70, 70–80
No. of students: 12, 30, x, 65, y, 25, 18
Total number of students = 229
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Median problems require cumulative frequency carefully.
Updated On: Mar 18, 2026
- 34, 45
- 25, 40
- 12, 18
- 30, 35
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Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Median class is 40–50 since median = 46.
Formula for median: Median = l + (N)/(2) - cff× h Here, l=40, h=10, f=65, N=229, (N)/(2)=114.5 Cumulative frequency before median class: 12+30+x = 42+x Substitute: 46 = 40 + (114.5-(42+x))/(65)× 10 6 = (72.5-x)/(65)× 10 x=25
Using total frequency: 12+30+25+65+y+25+18=229 y=40
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