Question

Given below are two statements.
Statement I - Adventive embryony gives rise to a condition called polyembryony.
Statement II - Generally, Nicotiana plants produced by non-recurrent apomixis are sterile and do not reproduce sexually.
In the light of the above statements, select the correct option given below:

• A. Both statement I and statement II are correct
• B. Both statement I and statement II are incorrect
• C. Statement I is correct but statement II is incorrect
• D. Statement I is incorrect but statement II is correct

Hint:

Check whether extra embryos from nucellus cells cause polyembryony and whether haploid apomicts are sterile.

Answer 1

The Correct Option is A

Step 1: Understanding the Concept
Apomixis is seed formation without normal fertilisation.

Step 2: Statement I
In adventive embryony, extra embryos arise from diploid nucellus or integument cells, so a seed has several embryos. This is polyembryony, so the statement is correct.

Step 3: Statement II
In non-recurrent apomixis the embryo develops from a haploid cell, so the plant is haploid and generally sterile, as in Nicotiana. This statement is also correct.

Final Answer:
Both statements are correct. \[ \boxed{\text{(A) }\text{Both statement I and statement II are correct}} \]