Step 1: Understanding the Question:
The question focuses on the biochemical properties and structural basis of Trehalose, a sugar important in stress tolerance.
Step 2: Detailed Explanation:
• Analyzing Assertion A: Trehalose is found in bacteria, fungi, insects, and "resurrection plants." It acts as a pharmaceutical stabilizer and an environmental protectant. Its high glass transition temperature allows it to form a "sugar glass" that coats and protects delicate protein and membrane structures from mechanical stress during drying. Thus, Assertion A is true.
• Analyzing Reason R: Trehalose consists of two glucose molecules joined by an $\alpha, \alpha$-1,1-glycosidic bond. Since the bond involves both C1 atoms (the anomeric/carbonyl carbons), no free aldehyde or ketone group is available. This makes it a non-reducing sugar. Thus, Reason R is true.
• Logical Connection: The lack of a reactive reducing end (Reason) makes the molecule chemically inert and extremely stable. This stability is exactly what allows it to be such an effective protectant (Assertion) without reacting with the proteins it is trying to save (avoiding Maillard reactions). Thus, R is the correct explanation of A.
Step 3: Final Answer:
Both statements are correct, and the non-reducing structural nature of trehalose is the chemical reason for its biological role as a stabilizer.