Step 1: Concept:
This problem compares two fundamental crystallographic properties—Atomic Packing Factor (APF) and the number of atoms per unit cell ($Z$)—for Simple Cubic (SC) and Face-Centered Cubic (FCC) lattice systems.
Step 2: Key Formula or Approach:
- Packing Fraction (APF) is the volume of atoms divided by the volume of the unit cell.
- SC Packing Fraction $\approx 0.52$ (52%)
- FCC Packing Fraction $\approx 0.74$ (74%)
- Atoms per unit cell ($Z$):
- SC: 8 corners $\times (1/8) = 1$ atom.
- FCC: 8 corners $\times (1/8) + 6$ faces $\times (1/2) = 1 + 3 = 4$ atoms.
Step 3: Step-by-step Explanation:
• Evaluating Assertion (A): The packing fraction of an FCC lattice (0.74) is mathematically higher than that of a Simple Cubic lattice (0.52). FCC is a closest-packed structure. Therefore, the assertion is undeniably correct.
• Evaluating Reason (R): The reason claims that FCC contains less atoms per unit cell than simple cubic. As calculated above, FCC contains $Z=4$ atoms per cell, while SC contains only $Z=1$. Thus, FCC contains more atoms per unit cell, making the Reason statement explicitly incorrect.
Step 4: Final Answer:
Assertion (A) is correct, but Reason (R) is factually false. This matches option (C).