Concept:
Transition metals exhibit characteristic metallic properties such as:
• High melting points
• High boiling points
• High enthalpy of atomization
• High density
These properties arise due to strong metallic bonding.
Unlike alkali metals, transition metals possess both \(ns\) and \((n-1)d\) electrons that participate in metallic bonding.
Step 1: Examine Assertion A.
Assertion states:
Generally, 3d transition metals have high melting points.
This statement is correct.
Examples:
\[
Cr,\ Fe,\ Co,\ Ni
\]
possess very high melting points because of strong metallic bonding.
Therefore Assertion A is true.
Step 2: Examine Reason R.
Reason states:
3d electrons along with 4s electrons participate in metallic bonding.
This is also correct.
Transition metals contain partially filled d-orbitals.
These d-electrons become delocalized and contribute significantly to metallic bond formation.
Hence the metallic bonding becomes much stronger than in s-block metals.
Therefore Reason R is true.
Step 3: Determine whether R explains A.
Because both 3d and 4s electrons contribute to metallic bonding:
Strength of metallic bonding increases
which results in:
Higher enthalpy of atomization
and consequently
Higher melting points
Thus the reason directly explains the assertion.
Step 4: Final conclusion.
Assertion A is correct.
Reason R is correct.
Reason R correctly explains Assertion A.
Therefore,
\[
\boxed{\text{Option (B)}}
\]