Concept:
Organic compounds containing double or triple bonds are called unsaturated compounds.
• Alkenes contain carbon-carbon double bonds.
• Alkynes contain carbon-carbon triple bonds.
These multiple bonds contain:
• One \( \sigma \)-bond
• One or more \( \pi \)-bonds
Important characteristics of \( \pi \)-bonds:
• \( \pi \)-bonds are weaker than \( \sigma \)-bonds.
• They are more exposed outside the internuclear axis.
• They break more easily during reactions.
Because of weak \( \pi \)-bonds, alkenes and alkynes readily undergo addition reactions.
Step 1: Examine Assertion A carefully.
Assertion A states:
“Alkenes and alkynes undergo addition reaction readily.”
This statement is correct.
Let us understand why.
Alkenes and alkynes contain multiple bonds:
\[
\mathrm{C=C}
\]
or
\[
\mathrm{C\equiv C}
\]
These bonds possess \( \pi \)-bonds in addition to \( \sigma \)-bonds.
During addition reactions:
• The weaker \( \pi \)-bond breaks.
• New atoms or groups add across the multiple bond.
For example:
Hydrogenation of ethene:
\[
\mathrm{CH_2=CH_2 + H_2 \rightarrow CH_3-CH_3}
\]
Here, the double bond opens and hydrogen atoms add across it.
Therefore, alkenes and alkynes indeed undergo addition reactions readily.
Hence, Assertion A is correct.
Step 2: Examine Reason R carefully.
Reason R states:
“Alkenes and alkynes undergo addition reaction because all the bonds present in them are strong \( \sigma \)-bonds.”
This statement is incorrect.
The major reason behind addition reactions is not the presence of strong \( \sigma \)-bonds.
In reality:
• Alkenes and alkynes contain weak \( \pi \)-bonds.
• \( \pi \)-bonds are more reactive and break easily.
A double bond contains:
\[
1\sigma + 1\pi
\]
A triple bond contains:
\[
1\sigma + 2\pi
\]
Thus, the reactivity is mainly due to:
\[
\boxed{\text{Weak } \pi \text{-bonds}}
\]
not due to strong \( \sigma \)-bonds.
Hence, Reason R is incorrect.
Step 3: Determine the correct relationship between A and R.
We observed:
• Assertion A is true.
• Reason R is false.
Therefore:
\[
\boxed{
\text{A is correct but R is not correct}
}
\]
Additional Explanation:
Why are \( \pi \)-bonds weaker?
\( \sigma \)-bonds form by head-on overlap of orbitals and are very strong.
\( \pi \)-bonds form by sideways overlap, which is less effective.
Therefore:
\[
\sigma \text{-bond strength} > \pi \text{-bond strength}
\]
Hence, \( \pi \)-bonds break easily during addition reactions.
Final Conclusion:
Assertion A is correct, but Reason R is incorrect.
Hence, the correct answer is:
\[
\boxed{(3)}
\]