Concept:
- A photon has zero rest mass, but the relativistic energy-momentum relation $E^2 = (pc)^2 + (mc^2)^2$ reduces to $E = pc$ when $m=0$, so a massless photon still carries momentum $p = E/c$.
- Pressure on a surface arises from the rate of change of momentum delivered to it, $F = \dfrac{dp}{dt}$, regardless of whether the particles carrying that momentum have mass.
Step 1: Check the momentum carried by an electromagnetic wave.
An electromagnetic wave is made of photons, each with energy $E=h\nu$ and momentum $p = \dfrac{E}{c} = \dfrac{h\nu}{c}$.
This momentum exists even though each photon has zero rest mass.
Step 2: Connect momentum delivery to pressure.
When photons strike a surface and are absorbed or reflected, they transfer momentum to it.
Force on the surface is the rate of this momentum transfer, $F = \dfrac{dp}{dt}$, and pressure is this force per unit area.
This confirms that electromagnetic waves do exert pressure, so Assertion (A) is true.
Step 3: Check the truth of Reason (R) on its own.
Photons are indeed massless particles, since they always travel at speed $c$ and a massive particle cannot do so.
So Reason (R) is also true as a standalone statement.
Step 4: Check whether (R) actually explains (A).
Radiation pressure exists because photons carry momentum, $p=E/c$, not because they lack mass.
Many massless things exert no pressure at all; what matters here is the momentum term, not the absence of mass.
So (R), while true, is not the reason behind (A).
Final Answer: Both (A) and (R) are true but (R) is not the correct explanation of (A).