Concept:
The angle between two lines in three-dimensional geometry is found using their direction ratios.
Step 1: Identify the direction ratios of first line.
\[
\frac{x+3}{3}=\frac{y-1}{5}=\frac{z+3}{4}
\]
So, direction ratios of first line are:
\[
a_1=3,\quad b_1=5,\quad c_1=4
\]
Step 2: Identify the direction ratios of second line.
\[
\frac{x+1}{1}=\frac{y-4}{1}=\frac{z-5}{2}
\]
So, direction ratios of second line are:
\[
a_2=1,\quad b_2=1,\quad c_2=2
\]
Step 3: Use the formula for angle between two lines.
\[
\cos\theta=\frac{a_1a_2+b_1b_2+c_1c_2}{\sqrt{a_1^2+b_1^2+c_1^2}\sqrt{a_2^2+b_2^2+c_2^2}}
\]
\[
\cos\theta=\frac{3(1)+5(1)+4(2)}{\sqrt{3^2+5^2+4^2}\sqrt{1^2+1^2+2^2}}
\]
\[
\cos\theta=\frac{3+5+8}{\sqrt{9+25+16}\sqrt{1+1+4}}
\]
\[
\cos\theta=\frac{16}{\sqrt{50}\sqrt{6}}
\]
\[
\cos\theta=\frac{16}{\sqrt{300}}
\]
\[
\cos\theta=\frac{16}{10\sqrt{3}}
\]
\[
\cos\theta=\frac{8}{5\sqrt{3}}
\]
Rationalizing,
\[
\cos\theta=\frac{8\sqrt{3}}{15}
\]
\[
\theta=\cos^{-1}\left(\frac{8\sqrt{3}}{15}\right)
\]
Therefore, Assertion is correct. Reason gives the correct formula and also explains Assertion.
\[
\therefore \text{Correct Answer is (A)}
\]