Question

Freundlich equation for adsorption of gases (in amount of x g) on a solid (in amount of m g) at constant temperature can be expressed as:

• A. \( \log\frac{x}{m}=\log p+\frac{1}{n}\log K \)
• B. \( \log\frac{x}{m}=\log K+\frac{1}{n}\log p \)
• C. \( \frac{x}{m}\propto p^n \)
• D. (x)/(m)=log p+(1)/(n)log K

Hint:

Freundlich isotherm is valid for heterogeneous surfaces.

Answer 1

The Correct Option is B

Step 1: Freundlich adsorption isotherm: (x)/(m)=Kp¹/n
Step 2: Taking logarithm: log(x)/(m)=log K+(1)/(n)log p