Question:

\(\frac{8}{4}\left(^{7}P_{4}\right)\) equals

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\(^{n}P_r = \frac{n!}{(n-r)!}\). Simplify factorials.
Updated On: Apr 25, 2026
  • \(^{8}P_{3}\)
  • \(^{8}C_{3}\)
  • \(^{8}P_{5}\)
  • \(^{8}P_{4}\)
  • \(^{8}C_{5}\)
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept:
\(^{7}P_4 = 7 \cdot 6 \cdot 5 \cdot 4 = 840\). Then \(\frac{8}{4} \times 840 = 2 \times 840 = 1680\). Now \(^{8}P_4 = 8 \cdot 7 \cdot 6 \cdot 5 = 1680\).

Step 2:
Detailed Explanation:
So expression = \(^{8}P_4\).

Step 3:
Final Answer:
Option (D).
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