Four point charges \(-Q\), \(-q\), \(2q\) and \(3Q\) are placed at corners of the square respectively. The relation between \(Q\) and \(q\) for which the potential at the centre of the square is zero, is
Show Hint
All charges are at the same distance from the centre, so the potential is zero when the algebraic sum of the charges is zero.
Step 1: Understanding the Concept
Potential is a scalar. Each corner is at the same distance \(r\) from the centre, so \(V=\dfrac{k}{r}(\text{sum of charges})\).
Step 2: Sum of charges
\(-Q-q+2q+3Q=2Q+q\)
Step 3: Calculation
\(V=0\) needs \(2Q+q=0\), so \(Q=-\dfrac{q}{2}\).
Final Answer:
The potential at the centre is zero when Q = −q/2.
\[ \boxed{\text{(B) }Q=-\dfrac{q}{2}} \]