Question:
Four groups of letters are given, three of them share a common relationship, while one is different. Choose the odd one out. (1) l g z, (2) f a t, (3) d y p, (4) v q j
Four groups of letters are given, three of them share a common relationship, while one is different. Choose the odd one out. (1) l g z, (2) f a t, (3) d y p, (4) v q j
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Check consistent position differences with cyclic alphabet
Updated On: Apr 21, 2026
- l g z
- f a t
- d y p
- v q j
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The Correct Option is C
Solution and Explanation
Step 1: Convert to positions:
l=12, g=7, z=26;
f=6, a=1, t=20;
v=22, q=17, j=10;
d=4, y=25, p=16.
Step 2: Check differences (cyclic if needed): l$\rightarrow$g: $-5$, g$\rightarrow$z: $+19$; f$\rightarrow$a: $-5$, a$\rightarrow$t: $+19$; v$\rightarrow$q: $-5$, q$\rightarrow$j: $-7$.
Step 3: First two groups follow pattern ($-5$, then large forward jump). Third group breaks consistency, and (d, y, p) does not follow similar structured differences.
Step 4: Hence, (d y p) is the odd one out $\Rightarrow$ option (C).
Step 2: Check differences (cyclic if needed): l$\rightarrow$g: $-5$, g$\rightarrow$z: $+19$; f$\rightarrow$a: $-5$, a$\rightarrow$t: $+19$; v$\rightarrow$q: $-5$, q$\rightarrow$j: $-7$.
Step 3: First two groups follow pattern ($-5$, then large forward jump). Third group breaks consistency, and (d, y, p) does not follow similar structured differences.
Step 4: Hence, (d y p) is the odd one out $\Rightarrow$ option (C).
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