Step 1: Statement I
Interference does not create or destroy energy. The energy missing at the dark fringes appears at the bright fringes, so the total energy is conserved. Statement I is true.
Step 2: Statement II
Fringe width is \(\beta = \dfrac{\lambda D}{d}\).
Higher frequency means shorter wavelength, since \(\lambda = \dfrac{c}{\nu}\).
Step 3: Conclusion
A smaller \(\lambda\) gives a smaller fringe width, so fringe width decreases with increasing frequency. Statement II is false.
Final Answer:
Statement I is true but Statement II is false.
\[ \boxed{\text{(D) }\text{Statement I is true but statement II is false.}} \]