Question:
For the reaction:
\[
\text{BaO} (s) + \text{O}_2(g) \rightarrow \text{BaO}_2(s)
\]
\( \Delta H = +ve \), In equilibrium condition, pressure of \( O_2 \) is dependent on:
For the reaction:
\[
\text{BaO} (s) + \text{O}_2(g) \rightarrow \text{BaO}_2(s)
\]
\( \Delta H = +ve \), In equilibrium condition, pressure of \( O_2 \) is dependent on:
Show Hint
The position of equilibrium in reactions with positive enthalpy changes shifts with temperature, as governed by Le Chatelier’s Principle.
Updated On: Jan 12, 2026
- mass of \( \text{BaO}_2 \)
- mass of \( \text{BaO} \)
- temperature of equilibrium
- mass of \( \text{BaO}_2 \) and \( \text{BaO} \) both
Show Solution
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The Correct Option is C
Solution and Explanation
Step 1: In reactions with a positive \( \Delta H \), the equilibrium position shifts with temperature. The pressure of \( O_2 \) is influenced by the temperature at equilibrium.
Final Answer: \[ \boxed{\text{temperature of equilibrium}} \]
Final Answer: \[ \boxed{\text{temperature of equilibrium}} \]
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