Question

For the reaction
\(\text{H}_2(g) + \text{Br}_2(g) \to 2 \text{HBr}(g)\),

the experimental data suggest the rate law
\(\text{Rate} = k[\text{H}_2][\text{Br}_2]^{1/2}\).
The molecularity and order of the reaction are respectively

• A. 2, (3)/(2)
• B. \(\dfrac{3}{2}, 2\)
• C. 1, 1
• D. 1, (1)/(2)

Hint:

Order comes from rate law, molecularity from reaction equation.

Answer 1

The Correct Option is A

Step 1: Molecularity is number of reacting molecules in the equation = 2.
Step 2: Order of reaction = 1 + (1)/(2) = (3)/(2)