Question

For the reaction CH\(_3\)COOH(l) + 2O\(_2\)(g) \(\rightarrow\) 2CO\(_2\)(g) + 2H\(_2\)O(l) at 25°C and 1 atm pressure, \(\Delta H = -874\) kJ. Then the change in internal energy (\(\Delta E\)) is

• A. -874 kJ
• B. -871.53 kJ
• C. -876.47 kJ
• D. +874 kJ

Hint:

When \(\Delta n_g = 0\), \(\Delta H = \Delta E\).

Answer 1

The Correct Option is A

Step 1: Understanding the Concept:
\(\Delta H = \Delta E + \Delta n_g RT\).
Step 2: Detailed Explanation:
\(\Delta n_g =\) moles gaseous products - moles gaseous reactants = 2 - 2 = 0
So \(\Delta H = \Delta E = -874\ \mathrm{kJ}\)
Step 3: Final Answer:
\(\Delta E = -874\) kJ.