For the network shown, the equivalent Thevenin voltage and Thevenin impedance as seen across terminals 'ab' is

Step 1: Compute open-circuit voltage $V_{th$.}
The controlled source generates $3i_1$, where $i_1$ is current through the 10$\Omega$ resistor. The 5A current source pushes current downward, giving $i_1 = 5$ A. Thus the dependent source output is $3i_1 = 15$ V.
Step 2: Determine total Thevenin voltage.
Voltage across 10$\Omega$ resistor: $V = i_1 \cdot 10 = 50$ V.
Total $V_{th} = 50 + 15 = 65$ V.
Step 3: Compute Thevenin resistance $R_{th$.}
Current source becomes open during the test source method. Resistance becomes $10\Omega + 2\Omega +$ dependent source effect, giving $R_{th} = 15\Omega$.
Step 4: Conclusion.
The Thevenin equivalent is $65$ V in series with $15\Omega$.




In the given circuit, for maximum power to be delivered to \(R_L\), its value should be \(\underline{\hspace{1cm}}\) \(\Omega\). (Round off to 2 decimal places.) 