For the network shown, the equivalent Thevenin voltage and Thevenin impedance as seen across terminals 'ab' is

Step 1: Compute open-circuit voltage $V_{th$.}
The controlled source generates $3i_1$, where $i_1$ is current through the 10$\Omega$ resistor. The 5A current source pushes current downward, giving $i_1 = 5$ A. Thus the dependent source output is $3i_1 = 15$ V.
Step 2: Determine total Thevenin voltage.
Voltage across 10$\Omega$ resistor: $V = i_1 \cdot 10 = 50$ V.
Total $V_{th} = 50 + 15 = 65$ V.
Step 3: Compute Thevenin resistance $R_{th$.}
Current source becomes open during the test source method. Resistance becomes $10\Omega + 2\Omega +$ dependent source effect, giving $R_{th} = 15\Omega$.
Step 4: Conclusion.
The Thevenin equivalent is $65$ V in series with $15\Omega$.

Find the values of $V_{Th}$ & $R_{Th}$ in the given circuit.
Given an open-loop transfer function \(GH = \frac{100}{s}(s+100)\) for a unity feedback system with a unit step input \(r(t)=u(t)\), determine the rise time \(t_r\).
Consider a linear time-invariant system represented by the state-space equation: \[ \dot{x} = \begin{bmatrix} a & b -a & 0 \end{bmatrix} x + \begin{bmatrix} 1 0 \end{bmatrix} u \] The closed-loop poles of the system are located at \(-2 \pm j3\). The value of the parameter \(b\) is: