Step 1: Understanding the Concept:
The given line passes through \((-1,2,-3)\) and has direction ratios \((1,2,3)\). We test each statement.
Step 2: Statement (A):
Check whether \((-2,0,-6)\) lies on the original line. Put \(t=-1\): \((-1-1,\,2-2,\,-3-3)=(-2,0,-6)\). Yes. Direction ratios are the same \((1,2,3)\). So (A) is correct.
Step 3: Statement (B):
The plane \(x-2y+z+8=0\) has normal \((1,-2,1)\). The point \((-1,2,-3)\) gives \(-1-4-3+8=0\), so it lies on the plane. The direction dot normal is \(1-4+3=0\), so the line is parallel to the plane. Hence the line lies in the plane. (B) is correct.
Step 4: Statement (C):
For the line to be perpendicular to the plane, its direction must be parallel to the normal \((1,-2,1)\). But \((1,2,3)\) is not a multiple of \((1,-2,1)\). So (C) is incorrect.
Step 5: Statement (D):
Put \(t=1\): \((0,4,0)\). Yes, it lies on the line. (D) is correct.
Step 6: Choose:
The incorrect statement is (C).
Final Answer:
Statement C is wrong, since the direction is not parallel to the normal.
\[ \boxed{C} \]