Step 1: Understanding the Concept
Compare with \(y=A\cos(kx+\omega t)\). Expanding, \(y=10\cos\left(\dfrac{\pi x}{4}+\dfrac{\pi t}{2}\right)\).
Step 2: Read the constants
\(A=10\ \text{m}\), \(k=\dfrac{\pi}{4}\ \text{rad/m}\), \(\omega=\dfrac{\pi}{2}\ \text{rad/s}\).
Step 3: Derived quantities
\(f=\dfrac{\omega}{2\pi}=0.25\ \text{Hz}\), \(\lambda=\dfrac{2\pi}{k}=8\ \text{m}\), \(v=\dfrac{\omega}{k}=2\ \text{m/s}\).
Step 4: Check the options
Only the frequency of \(0.25\ \text{Hz}\) matches. The wavelength is 8 m, not 10 m, the speed is 2 m/s, not 20 cm/s, and the angular velocity is \(\dfrac{\pi}{2}\), not \(2\pi\).
Final Answer:
The correct statement is that the frequency is 0.25 Hz.
\[ \boxed{\text{(A) }\text{frequency } = 0.25\ \text{Hz}} \]