For the equilibrium \(\mathrm{A} \rightleftharpoons \mathrm{B}\), the variation of the rate of the forward (a) and reverse (b) reaction with time is given by :
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The Correct Option is C
Solution and Explanation
At equilibrium \(r_f = r_b\), so the two curves approach each other and merge into one horizontal line at the same rate value.
The graph with curve a falling, curve b rising and both meeting at one common point is correct. The graph where the curves only cross and then separate, the one where they stay apart with a gap at equilibrium, and the one where they diverge are all wrong.
Answer: (3) the graph in which curves a and b converge to one common point at equilibrium
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