Concept:
Voltage across capacitor:
\[
V_C = I X_C
\]
Step 1: Given values
\[
X_L = 20\Omega,\quad X_C = 20\Omega,\quad R = 10\Omega
\]
Step 2: Resonance condition
\[
X_L = X_C \Rightarrow \text{resonance}
\]
Step 3: Impedance
\[
Z = R = 10\Omega
\]
Step 4: Current
\[
I = \frac{200}{10} = 20A
\]
Step 5: Voltage across capacitor
\[
V_C = I X_C = 20 \times 20 = 400V
\]
Phase is \(-90^\circ\).
Final Answer:
\[
\boxed{400\angle -90^\circ V}
\]