Step 1: Formula
Magnifying power of an astronomical telescope in normal adjustment is \(M=\frac{f_o}{f_e}\).
Step 2: Meaning
To make \(M\) large, \(f_o\) must be large and \(f_e\) small. Among the options, only "focal length of objective is large" fits. Option (B).
Final Answer:
A large objective focal length gives a large magnification, option (B).
\[ \boxed{\text{(B)}} \]