




Step 1: Analyze the Reaction
The reaction involves KMnO₄/H⁺, which is a typical oxidizing agent that cleaves alkenes and oxidizes the resulting fragments to carboxylic acids.
Step 2: Predict the Major Product
The oxidation of an alkene will cleave the double bond and convert both fragments into carboxylic acids. The correct product is:
$$ \text{COOH} \longrightarrow -C - C \longrightarrow \text{COOH} $$
Conclusion
The correct product is a pair of carboxylic acids formed by cleaving the alkene.
3A → 2B,rate of reaction +d[B]/dt is equals to

List-I | List-II | ||
| (A) | ![]() | (I) | ![]() |
| (B) | ![]() | (II) | CrO3 |
| (C) | ![]() | (III) | KMnO4/KOH, \(\Delta\) |
| (D) | ![]() | (IV) | (i) O3 (ii) Zn-H2O |