Step 1: Understanding the Concept
For a first-order reaction, \(t_{1/2} = \dfrac{0.693}{k}\), independent of concentration.
Step 2: Substitute
\(k = 6\times 10^{-4}\text{ s}^{-1}\), so \(t_{1/2} = \dfrac{0.693}{6\times 10^{-4}}\).
Step 3: Result
\(t_{1/2} = 1155\) s.
Final Answer:
The half-life is 1155 seconds.
\[ \boxed{\text{(C) }1155} \]