Question:

For first order reaction, the rate constant for the decomposition of \(\text{N}_{2}\text{O}_{5}\) is \(6\times 10^{-4}\) s\({}^{-1}\). Calculate half life period for decomposition in terms of seconds

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For a first-order reaction, half-life equals 0.693 divided by the rate constant.
Updated On: Nov 12, 2026
  • \(1100\)
  • \(1225\)
  • \(1155\)
  • \(1050\)
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept
For a first-order reaction, \(t_{1/2} = \dfrac{0.693}{k}\), independent of concentration.

Step 2: Substitute
\(k = 6\times 10^{-4}\text{ s}^{-1}\), so \(t_{1/2} = \dfrac{0.693}{6\times 10^{-4}}\).

Step 3: Result
\(t_{1/2} = 1155\) s.

Final Answer:
The half-life is 1155 seconds. \[ \boxed{\text{(C) }1155} \]
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