Question:

For any two points \( P, Q \in \mathbb{R}^3 \), let \( \vec{P, Q} \) denote the vector from the point \( P \) to the point \( Q \) and let \( d(P, Q) \) denote the length of \( \vec{P, Q} \). Let \( F: \mathbb{R}^3 \to \mathbb{R}^3 \) be a linear transformation such that

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Isometries in \( \mathbb{R}^3 \) preserve lengths, angles, and the cross product, but they are not always surjective, particularly when they involve transformations like reflections or rotations that do not cover the entire space.
Updated On: Jun 1, 2026
  • \( F \) is an injective map.
  • \( F \) is a surjective map.
  • For any four points \( P, Q, R, S \in \mathbb{R}^3 \), we have \[ \vec{(F(P), F(Q))} \cdot \vec{(F(R), F(S))} = \vec{(P, Q)} \cdot \vec{(R, S)}, \] where \( \cdot \) denotes the usual dot product in \( \mathbb{R}^3 \).
  • For any four points \( P, Q, R, S \in \mathbb{R}^3 \), we have \[ \vec{(F(P), F(Q))} \times \vec{(F(R), F(S))} = \vec{(P, Q)} \times \vec{(R, S)}, \] where \( \times \) denotes the usual cross product in \( \mathbb{R}^3 \).
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The Correct Option is B

Solution and Explanation

Step 1: Analyzing injectivity and surjectivity of \( F \).
Since the transformation \( F \) preserves distances, it is a type of isometry, meaning the transformation does not distort distances. Isometries in \( \mathbb{R}^3 \) can be either translations, rotations, or reflections, which preserve distances but may or may not be injective or surjective. Statement (B) is false because not all isometries are surjective.

Step 2: Check statement (A) on injectivity.
Isometries are injective because if \( F(P) = F(Q) \), then the distances are preserved, implying that \( P = Q \). Therefore, statement (A) is true.

Step 3: Analyze statement (C) involving dot product.
Since \( F \) preserves distances and is a linear transformation, the dot product is preserved. Therefore, statement (C) is true.

Step 4: Analyze statement (D) involving cross product.
The preservation of the cross product is also a property of isometries. The magnitude and direction of the vectors in the cross product are preserved, so statement (D) is true.

Step 5: Conclusion.
From the analysis, we conclude that statement (B) is false because \( F \) may not always be surjective, even though it is an isometry. Therefore, the correct answer is (B).
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