Question:
For a uniformly charged plane sheet, the variation of electric field (E) with distance (d) is correctly shown graphically in graph
For a uniformly charged plane sheet, the variation of electric field (E) with distance (d) is correctly shown graphically in graph
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The field of an infinite uniformly charged sheet is sigma/(2 epsilon0), independent of distance.
Updated On: Oct 1, 2026
- A
- B
- C
- D
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept
By Gauss law, an infinite uniformly charged plane sheet with surface charge density \(\sigma\) produces a field \(E = \dfrac{\sigma}{2\varepsilon_0}\) on either side of it.
Step 2: Read the graphs
The field does not contain the distance \(d\), so the E-d graph is a horizontal straight line.
Graph (A) shows E rising linearly from zero, which is the field inside a uniformly charged solid sphere. Graph (B) shows E falling with distance, which does not happen for an infinite sheet. Graph (D) is a vertical line, which is not a function of d. Graph (C) is a horizontal line starting above the origin, the constant field.
Final Answer:
The field is constant with distance, graph (C). \[ \boxed{\text{Graph (C)}} \]
By Gauss law, an infinite uniformly charged plane sheet with surface charge density \(\sigma\) produces a field \(E = \dfrac{\sigma}{2\varepsilon_0}\) on either side of it.
Step 2: Read the graphs
The field does not contain the distance \(d\), so the E-d graph is a horizontal straight line.
Graph (A) shows E rising linearly from zero, which is the field inside a uniformly charged solid sphere. Graph (B) shows E falling with distance, which does not happen for an infinite sheet. Graph (D) is a vertical line, which is not a function of d. Graph (C) is a horizontal line starting above the origin, the constant field.
Final Answer:
The field is constant with distance, graph (C). \[ \boxed{\text{Graph (C)}} \]
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