Step 1: Understanding the Question:
The problem asks us to evaluate four operational entries in a given truth table for a standard two-input AND logic gate and determine which combinations are technically correct.
Step 2: Key Formula or Approach:
The boolean expression representing the operation of a two-input AND gate is:
$$Y = A \cdot B$$
An AND gate output is HIGH ($1$) if and only if all its inputs are simultaneously HIGH ($1$). If any input is LOW ($0$), the output is automatically LOW ($0$).
Step 3: Detailed Explanation:
Let's systematically test each of the four truth table entries against the boolean multiplication rule:
1.
Entry 1: Inputs $A = 0, B = 1$. Output $Y = 0 \cdot 1 = 0$. This entry is
correct.
2.
Entry 2: Inputs $A = 1, B = 0$. Output $Y = 1 \cdot 0 = 0$. This entry is
correct.
3.
Entry 3: Inputs $A = 1, B = 1$. Output $Y = 1 \cdot 1 = 1$. This entry is
correct.
4.
Entry 4: Inputs $A = 0, B = 0$. Output $Y = 0 \cdot 0 = 0$. However, the table entry lists $Y = 1$, which makes this entry
incorrect.
Reviewing our findings, entries 1, 2, and 3 are correct, while entry 4 is false.
Step 4: Final Answer:
The correct entries are 1, 2 and 3 only, which matches option (B).