The correct answer is (C) : 3.13 × 105 ms–1
λobs = λsource \(\sqrt{\frac{1+\frac{ν}{C}}{1-\frac{v}{C}}}\)
For ν << C,
\(\frac{670.7}{670}\) = 1 + \(\frac{ν}{C}\)
⇒ ν = \(\frac{0.7}{670}\) × 3 × \(10^8\) m/s
⇒ ν ≃ 3.13 × \(10^5\) m/s

In the following \(p\text{–}V\) diagram, the equation of state along the curved path is given by \[ (V-2)^2 = 4ap, \] where \(a\) is a constant. The total work done in the closed path is: 