Question:

For a reaction \(\mathrm{X + Y \rightleftharpoons 2Z}\), 1.0 mol of X, 1.5 mol of Y and 0.5 mol of Z were taken in a 1 L vessel and allowed to react. At equilibrium, the concentration of Z was 1.0 mol L-1. The equilibrium constant of reaction is \(\frac{x}{15}\). The value of x is _________.

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Z rises from 0.5 to 1.0 M, so the extent of reaction is 0.25 M; X and Y each fall by 0.25 M. Then \(K_c = \frac{[Z]^2}{[X][Y]}\).
Updated On: Nov 5, 2026
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Correct Answer: 16

Solution and Explanation

Volume is 1 L, so moles = molarity.
Let X and Y each react by a; Z formed = 2a.
[Z]eq = 0.5 + 2a = 1.0, so a = 0.25.
[X]eq = 1.0 - 0.25 = 0.75 M; [Y]eq = 1.5 - 0.25 = 1.25 M; [Z]eq = 1.0 M.
\(K_c = \frac{(1.0)^2}{0.75 \times 1.25} = \frac{1}{0.9375} = \frac{16}{15}\).
Comparing with \(\frac{x}{15}\): x = 16.
Answer: 16
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