For a Poisson distribution where the mean is \(4\), what is the value of the third central moment?
Show Hint
For a Poisson distribution, several moments have simple forms:
\[
\text{Mean} = \text{Variance} = \text{Third central moment} = \lambda
\]
This property makes calculations involving Poisson moments very straightforward.
Concept:
For a Poisson distribution with parameter \( \lambda \):
Mean \(= \lambda\)
Variance \(= \lambda\)
The third central moment \( \mu_3 \) is also equal to \( \lambda \)
Thus,
\[
\mu_3 = \lambda
\]
Step 1: Identify the parameter of the distribution.
The mean of the Poisson distribution is given as:
\[
\lambda = 4
\]
Step 2: Use the formula for the third central moment.
\[
\mu_3 = \lambda
\]
Substituting the value:
\[
\mu_3 = 4
\]
\[
\therefore \text{The third central moment is } 4
\]