Concept:
For a first order reaction, the rate of reaction depends directly on the concentration of one reactant. The general rate law is:
\[
\text{Rate} = k[A]
\]
where \(k\) is the rate constant and \([A]\) is the concentration of reactant.
Step 1: Check statement A.
For a first order reaction, half-life is given by:
\[
t_{1/2} = \frac{0.693}{k}
\]
This formula does not contain initial concentration. Therefore, the half-life of a first order reaction is independent of initial concentration.
\[
A \text{ is correct}
\]
Step 2: Check statement B.
For a first order reaction:
\[
\text{Rate} = k[A]
\]
The unit of rate is:
\[
\text{mol L}^{-1}\text{s}^{-1}
\]
The unit of concentration is:
\[
\text{mol L}^{-1}
\]
So,
\[
k = \frac{\text{Rate}}{[A]}
\]
\[
k = \frac{\text{mol L}^{-1}\text{s}^{-1}}{\text{mol L}^{-1}}
\]
\[
k = s^{-1}
\]
Therefore, the unit of rate constant for a first order reaction is \(s^{-1}\).
\[
B \text{ is correct}
\]
Step 3: Check statement C.
The integrated rate equation for a first order reaction is:
\[
\ln[A] = \ln[A]_0 - kt
\]
This equation is similar to:
\[
y = c + mx
\]
Hence, the plot of \(\ln[A]\) versus time is a straight line.
\[
C \text{ is correct}
\]
Step 4: Check statement D.
For a first order reaction:
\[
\text{Rate} = k[A]
\]
This shows that the rate depends on reactant concentration. Therefore, the statement that rate is independent of reactant concentration is wrong.
\[
D \text{ is incorrect}
\]
Thus, correct statements are:
\[
A, B \text{ and } C \text{ only}
\]
\[
\therefore \text{Correct Answer is (A)}
\]