Question:
For a certain reaction, the enthalpy change and entropy change are \(+50\) kJ and \(-50\) J/K respectively at \(27^{\circ }\)C, What is the Gibbs free energy change of reaction?
For a certain reaction, the enthalpy change and entropy change are \(+50\) kJ and \(-50\) J/K respectively at \(27^{\circ }\)C, What is the Gibbs free energy change of reaction?
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Use the relation delta G equals delta H minus T delta S with the entropy converted to kJ per kelvin.
Updated On: Nov 12, 2026
- \(-65\) kJ
- \(35\) kJ
- \(-35\) kJ
- \(65\) kJ
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The Correct Option is D
Solution and Explanation
Step 1: Understanding the Concept
The Gibbs free energy change is \(\Delta G=\Delta H-T\Delta S\).
Step 2: Data
\(\Delta H=+50\ \text{kJ}\), \(\Delta S=-50\ \text{J K}^{-1}=-0.05\ \text{kJ K}^{-1}\), \(T=27+273=300\) K.
Step 3: Calculation
\(\Delta G=50-300\times(-0.05)=50+15=+65\ \text{kJ}\).
Final Answer:
The Gibbs free energy change is positive 65 kJ. \[ \boxed{\text{(D) }65\ \text{kJ}} \]
The Gibbs free energy change is \(\Delta G=\Delta H-T\Delta S\).
Step 2: Data
\(\Delta H=+50\ \text{kJ}\), \(\Delta S=-50\ \text{J K}^{-1}=-0.05\ \text{kJ K}^{-1}\), \(T=27+273=300\) K.
Step 3: Calculation
\(\Delta G=50-300\times(-0.05)=50+15=+65\ \text{kJ}\).
Final Answer:
The Gibbs free energy change is positive 65 kJ. \[ \boxed{\text{(D) }65\ \text{kJ}} \]
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