Question:
For a certain reaction, change in enthalpy is \(-225\) kJ and entropy change \(=-150\) JK\({}^{-1}\). Find the temperature so that \(\Delta G\) is zero.
For a certain reaction, change in enthalpy is \(-225\) kJ and entropy change \(=-150\) JK\({}^{-1}\). Find the temperature so that \(\Delta G\) is zero.
Show Hint
Set Delta G equal to Delta H minus T Delta S equal to zero and solve for T, keeping units consistent.
Updated On: Nov 12, 2026
- \(350\) K
- \(1500\) K
- \(105\) K
- \(1800\) K
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept
The Gibbs equation is \(\Delta G=\Delta H-T\Delta S\).
At \(\Delta G=0\), \(T=\dfrac{\Delta H}{\Delta S}\).
Step 2: Convert the Units
\(\Delta H=-225\) kJ \(=-225000\) J
\(\Delta S=-150\) J K\(^{-1}\)
Step 3: Calculation
\(T=\dfrac{-225000}{-150}=1500\) K
Step 4: Compare the options
The value matches option (B).
Final Answer:
Delta G is zero at 1500 K. \[ \boxed{\text{(B) }\text{1500 K}} \]
The Gibbs equation is \(\Delta G=\Delta H-T\Delta S\).
At \(\Delta G=0\), \(T=\dfrac{\Delta H}{\Delta S}\).
Step 2: Convert the Units
\(\Delta H=-225\) kJ \(=-225000\) J
\(\Delta S=-150\) J K\(^{-1}\)
Step 3: Calculation
\(T=\dfrac{-225000}{-150}=1500\) K
Step 4: Compare the options
The value matches option (B).
Final Answer:
Delta G is zero at 1500 K. \[ \boxed{\text{(B) }\text{1500 K}} \]
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