Question:
For a body in simple harmonic motion. Potential energy (PE), Kinetic energy (KE), Total energy (TE) are measured as a function of displacement x. Which of the following statements is true?
For a body in simple harmonic motion. Potential energy (PE), Kinetic energy (KE), Total energy (TE) are measured as a function of displacement x. Which of the following statements is true?
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At the center, speed is peak (KE max); at the ends, the spring is stretched (PE max).
Updated On: Jun 6, 2026
- KE is maximum when x = 0
- TE is zero when x = 0
- KE is maximum when x is maximum
- PE is maximum when x = 0
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The Correct Option is A
Solution and Explanation
Step 1: Concept
Energy in Simple Harmonic Motion (SHM).
Step 2: Meaning
At equilibrium ($x=0$), velocity is maximum. At amplitude ($x=A$), velocity is zero.
Step 3: Analysis
Kinetic energy $KE = \frac{1}{2} k (A^2 - x^2)$. It is maximum at $x=0$. Potential energy $PE = \frac{1}{2} k x^2$. It is maximum at $x=A$. Total energy is constant.
Step 4: Conclusion
KE is maximum when displacement $x$ is 0.
Final Answer: (A)
Energy in Simple Harmonic Motion (SHM).
Step 2: Meaning
At equilibrium ($x=0$), velocity is maximum. At amplitude ($x=A$), velocity is zero.
Step 3: Analysis
Kinetic energy $KE = \frac{1}{2} k (A^2 - x^2)$. It is maximum at $x=0$. Potential energy $PE = \frac{1}{2} k x^2$. It is maximum at $x=A$. Total energy is constant.
Step 4: Conclusion
KE is maximum when displacement $x$ is 0.
Final Answer: (A)
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