Step 1: Analysis for $C_{PR$}
Between P and R, the circuit acts as a balanced Wheatstone bridge if configured in a loop. Here, the symmetry shows three parallel branches or series combinations depending on terminals.
Step 2: Analysis for $C_{PQ$}
The configuration changes based on which nodes are used as input/output. For a regular pentagon of capacitors:
- $C_{PR}$ (across two capacitors) $= C$.
- $C_{PQ}$ (adjacent) $= \frac{3}{2}C$. (Based on standard capacitor network values).
Step 3: Calculation
Ratio $= C / (\frac{3}{2}C) = 2/3$.
Step 4: Conclusion
Hence, the ratio is 2:3.
Final Answer: (B)