Question:
Find the pH of \(0.02\ \text{M}\ \text{HCl}\).
Find the pH of \(0.02\ \text{M}\ \text{HCl}\).
Show Hint
HCl is a strong acid, so [H+] equals the acid concentration and pH = -log [H+].
Updated On: Nov 12, 2026
- \(1.7\)
- \(2.7\)
- \(1.5\)
- \(2.5\)
Show Solution
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept
HCl is a strong acid and ionises completely, so \([\text{H}^{+}]=0.02\ \text{M}\).
Step 2: Formula
\(\text{pH}=-\log[\text{H}^{+}]\)
Step 3: Calculation
\(\text{pH}=-\log(2\times 10^{-2})=2-\log 2=2-0.301=1.7\)
Final Answer:
The pH of the solution is 1.7. \[ \boxed{\text{(A) }1.7} \]
HCl is a strong acid and ionises completely, so \([\text{H}^{+}]=0.02\ \text{M}\).
Step 2: Formula
\(\text{pH}=-\log[\text{H}^{+}]\)
Step 3: Calculation
\(\text{pH}=-\log(2\times 10^{-2})=2-\log 2=2-0.301=1.7\)
Final Answer:
The pH of the solution is 1.7. \[ \boxed{\text{(A) }1.7} \]
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