Question:
Find the p\(\text{K}_{b}\) of the weak base BOH, if its \(\text{K}_{b}\) is \(1\times 10^{-5}\) ?
Find the p\(\text{K}_{b}\) of the weak base BOH, if its \(\text{K}_{b}\) is \(1\times 10^{-5}\) ?
Show Hint
pKb is the negative logarithm of Kb.
Updated On: Nov 12, 2026
- \(-5\)
- \(5\)
- \(10\)
- \(10^{-5}\)
Show Solution
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept
\(pK_b=-\log K_b\).
Step 2: Calculation
\(pK_b=-\log(1\times10^{-5})=-(-5)=5\).
Step 3: Check
A base with a small \(K_b\) is weak, and a larger \(pK_b\) means a weaker base, so 5 is reasonable.
Final Answer:
The pKb of BOH is 5. \[ \boxed{\text{(B) }5} \]
\(pK_b=-\log K_b\).
Step 2: Calculation
\(pK_b=-\log(1\times10^{-5})=-(-5)=5\).
Step 3: Check
A base with a small \(K_b\) is weak, and a larger \(pK_b\) means a weaker base, so 5 is reasonable.
Final Answer:
The pKb of BOH is 5. \[ \boxed{\text{(B) }5} \]
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