Concept:
The oxidation state of an element is calculated by assuming:
Hydrogen = \(+1\)
Oxygen = \(-2\)
Sum of oxidation states in a neutral compound = \(0\)
Step 1: {Find oxidation state of P in \(H_3PO_4\).}
Let oxidation state of phosphorus = \(x\)
\[
3(+1) + x + 4(-2) = 0
\]
\[
3 + x - 8 = 0
\]
\[
x -5 = 0
\]
\[
x = +5
\]
Step 2: {Find oxidation state of P in \(H_3PO_3\).}
Let oxidation state of phosphorus = \(x\)
\[
3(+1) + x + 3(-2) = 0
\]
\[
3 + x - 6 = 0
\]
\[
x -3 = 0
\]
\[
x = +3
\]
Step 3: {Conclusion.}
\[
H_3PO_4 : +5
\]
\[
H_3PO_3 : +3
\]