Step 1: Write the inverse of the complex number.
The multiplicative inverse of a complex number \( z = a + bi \) is given by:
\[
z^{-1} = \frac{1}{z} = \frac{1}{a + bi}
\]
For \( z = \sqrt{5} + 3i \), the multiplicative inverse will be:
\[
z^{-1} = \frac{1}{\sqrt{5} + 3i}
\]
Step 2: Multiply by the conjugate.
To simplify, we multiply both the numerator and denominator by the conjugate of \( \sqrt{5} + 3i \), which is \( \sqrt{5} - 3i \):
\[
z^{-1} = \frac{1}{\sqrt{5} + 3i} \times \frac{\sqrt{5} - 3i}{\sqrt{5} - 3i}
\]
\[
z^{-1} = \frac{\sqrt{5} - 3i}{(\sqrt{5})^2 + (3i)^2} = \frac{\sqrt{5} - 3i}{5 - 9} = \frac{\sqrt{5} - 3i}{-4}
\]
Step 3: Simplify the result.
Now, simplify the expression:
\[
z^{-1} = -\frac{\sqrt{5}}{4} + \frac{3i}{4}
\]
Step 4: Conclusion.
The multiplicative inverse of \( \sqrt{5} + 3i \) is:
\[
z^{-1} = -\frac{\sqrt{5}}{4} + \frac{3i}{4}
\]